Question

The first step of glucose metabolism is the formation of glucose-6-phosphate. Under a certain condition, Glucose...

The first step of glucose metabolism is the formation of glucose-6-phosphate. Under a certain condition,

Glucose + ATP ⇌ Glucose-6-phosphate + ADP ΔG = - 17 kJ/mol at the same condition,

ATP + H2O ⇌ ADP + Pi ΔG = - 30 kJ.mol-1

Calculate the free energy change of the following reaction:

Glucose + Pi ⇌ Glucose-6-phosphate

Please explain it as well as possible... Please help me figure out why the answer is 13 Kj/Mol... I keep on getting confused on what goes first I guess, or am I supposed to flip the sign, or what? My teacher explained it horribly!

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Answer #1

The desired reaction is Glucose + Pi giving Glucose-6-phosphate

Since glucose is present in the left hand side in the dersired reaction and also in the reaction 1, hence we don't need to reverse the reaction

secondly the reaction 2 must be reverse in order to get the Pi in the left hand side to get the Glucose-6-phosphate

reversing the second reaction

Adding both the reactions we obtained the desired reaction

Delta G = Delta (G1) - Delta (G2) = -17 kJ -(-30 kJ) = 13 kJ/mol

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