Which of these solutions has a higher boiling point: 0.35 m CaCl2 or 0.9 m urea [(NH2)2CO]. State your reason.
T = i*m*Kb
CaCl2 -----> Ca+2 + 2Cl-
total three ions i = 3
T = i*m*Kb
= 3*0.35*0.512
= 0.5376C0
urea [(NH2)2CO] not ionisable i=1
T = i*m*Kb
= 1*0.9*0.512
= 0.4608C0
number of ions are increases boliling point is increases.
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