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how many grams of anhydrous cobalt (II)chloride would remain behind after strongly heating 25.0g of CoCl2•6H2O

how many grams of anhydrous cobalt (II)chloride would remain behind after strongly heating 25.0g of CoCl2•6H2O

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Answer #1

CoCl2 . 6H2O --------> CoCl2 + 6 H2O

238 g of CoCl2 . 6H2O produces 130 g of CoCl2

25 g of CoCl2 . 6H2O produces (130 / 238) * 25 g of CoCl2

                                                        = 13.655 g of CoCl2

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