Question

A.) Pick an appropriate solvent to dissolve acetic acid (polar, contains an OH group) .

Water (H₂O)

Acetone (CH₃COCH₃)

Methanol (CH₃OH)

Ethanol (CH₃CH₂OH)

Hexane (C₆H₁₄)

Diethyl ether (CH₃CH₂OCH₂CH₃)

Toluene (C₇H₈)

Carbon tetrachloride (CCl₄)

B.) State the kind of intermolecular forces that would occur between the solute and solvent in acetic acid (polar, contains an OH group) solution.

Dispersion

Hydrogen bonding

Ion-dipole

Dipole-dipole

C.) Pick an appropriate solvent to dissolve sodium chloride (ionic).

(Same answer choices as Part A)

D.) State the kind of intermolecular forces that would occur between the solute and solvent in sodium chloride (ionic) solution.

(Same answer choices as Part B)

E.) Pick an appropriate solvent to dissolve olive oil (nonpolar).

(Same answer choices as Part A)

F.) State the kind of intermolecular forces that would occur between the solute and solvent in olive oil (nonpolar) solution.

(Same answer choices as Part B)

G.) Pick an appropriate solvent to dissolve sodium nitrate (ionic)

(Same answer choices as Part A)

H.) State the kind of intermolecular forces that would occur between the solute and solvent in sodium nitrate (ionic) solution.

(Same answer choices as Part B)

Answer 1

A.) Pick an appropriate solvent to dissolve acetic acid (polar, contains an OH group) .

Water (H₂O)

H2O take part in hydrogen bonding with acetic acid. Hence acetic acid is completely dissolve in water.

B.)

Hydrogen bonding

acetic acid contains -COOH group which take part in hydrogen bonding with H2O.

C.) Water (H₂O) because NaCl ionic compound and due to ion dipole interaction NaCl is dissolved in water.

D.) Ion-dipole

NaCl (aq)..............> Na+ (aq) + Cl- (aq)

In aqueous solution, NaCl produce Na+ and Cl- ions. water have dipoles.

thus ion-dipole interaction occurs.

E.) Hexane (C₆H₁₄) because nonpolar oil dissolve in non polar solvents.

F.) Dispersion because oil is nonpolar in nature.

G.) Water (H₂O) because NaNO3 is ionic compound and due to ion dipole interaction NaNO3 is dissolved in water.

H.) NaNO3 (aq)...........> Na+ (aq) + NO3- (aq)

Ion-dipole is the answer.