Question

Poly(vinyl acetate) of number-average molecular weight of
100,000 is hydrolyzed to poly(vinyl alcohol). Oxidation of the
latter with periodic acid to cleave 1,2-diol linkages yield a
poly(vinyl alcohol) with X_{n} = 200. Calculate the
percentage of head-to-tail and head-to-head linkages in the
poly(vinyl acetate).

Answer #1

Poly(vinyl)alcohol is given by the head to tail linked polymer. Therefore number of vinyl acetate monomeric units involve in forming Poly(vinyl)alcohol is 200.

The weight of one vinyl acetate unit=86 g/mol

Therefore the weight of 200 units=86*200=17200

The weight of the poly vinyl acetate polymer only due to this=100000-17200=82800

Therefore the percentage of head to tail linkages=(17200/100000)*100=17.2%

the percentage of head to head linkages=(82800/100000)*100=82.8%

The tensile strength of a poly(methyl methacrylate) (PMMA)
polymer with a number-average molecular weight of 30,00 g/mol is
found to be 50 MPa, while the tensile strength of a second sample
having a number average molecular weight of 50,000 g/mol is 150
MPa.
a) Estimate the tensile strength at a number average molecular
weight of 40,000 g/mol.
b) Estimate the tensile strength at a number average molecular
weight of 1,000 g/mol.
c) Estimate the tensile strength at a number average...

The number-average molecular weight of a poly(styrene-butadiene)
alternating copolymer is 1346000 g/mol; determine the average
number of (a) styrene and
(b)butadiene repeat units per molecule.

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 6 minutes ago

asked 33 minutes ago

asked 47 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago