Poly(vinyl acetate) of number-average molecular weight of 100,000 is hydrolyzed to poly(vinyl alcohol). Oxidation of the latter with periodic acid to cleave 1,2-diol linkages yield a poly(vinyl alcohol) with Xn = 200. Calculate the percentage of head-to-tail and head-to-head linkages in the poly(vinyl acetate).
Poly(vinyl)alcohol is given by the head to tail linked polymer. Therefore number of vinyl acetate monomeric units involve in forming Poly(vinyl)alcohol is 200.
The weight of one vinyl acetate unit=86 g/mol
Therefore the weight of 200 units=86*200=17200
The weight of the poly vinyl acetate polymer only due to this=100000-17200=82800
Therefore the percentage of head to tail linkages=(17200/100000)*100=17.2%
the percentage of head to head linkages=(82800/100000)*100=82.8%
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