Question

The concentration of carbon monoxide in an urban apartment is 48 micrograms/m^3. What mass of carbon monoxide in grams is present in a room measuring 10.6 ft x 14.8 ft x 20.5 ft ?

Answer 1

we have 1 ft = 0.3048 m

volume of the room = 10.6 * 0.3048 * 14.8 * 0.3048 * 20.5 * 0.3048

Volume of the room = 91.068 m^3

concentration of CO 48 * 10^-6 g in 1 m^3

91.068 m^3 have (48 *10^-6 * 91.068) g

                              = 4.371 * 10^-3 g

                              = 4.371 mg