Question

The reaction A→B has been experimentally determined to be second order. The initial rate is 0.0100M/s...

The reaction A→B has been experimentally determined to be second order. The initial rate is 0.0100M/s at an initial concentration of A of 0.150 M .

1. What is the initial rate at [A]=0.850 M ?

a. 0.321 M/s
b. 0.113 M/s
c. 5.67×10−2 M/s
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Answer #1

Answer:-

For a second order reaction the Rate = K[A]2

Here, Rate = 0.0100 M/s

Initial concentration [A] = 0.150 M

Hence Rate constant K = 0.0100 / (0.150)2

= 0.0100 / 0.0225

= 0.4444 M-1S-1

Thus when initial [A] = 0.850 M

Then Rate = 0.4444 (0.850)2

= 0.4444 0.7225

= 0.321 M/S

     

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