Question

A mixture containing an initial concentration of 0.1391 M for both CO and Cl₂ is allowed to come to equilibrium (see reaction below). What must be the equilibrium concentration of COCl₂?

CO(g) + Cl₂(g) ↔ COCl₂(g) K_c = 1.23e3

	0.1288 M
	0.1794 M
	0.0959 M
	0.0731 M

Answer 1

answer : 0.1288 M

CO(g) + Cl₂(g) <-----------------> COCl₂(g)                K_c = 1.23 x 10^3

0.1391         0.1391                                0

0.1391 - x      0.1391-x                            x

Kc = x / (0.1391-x)^2

1.23 x 10^3 = x / (0.1391-x)^2

by solving this

x = 0.1288

equilibrium concentration of [COCl2] = 0.1288 M