Suppose that a catalyst lowers the activation barrier of a reaction from 122 kJ/mol to 57 kJ/mol .
By what factor would you expect the reaction rate to increase at 25 ∘C? (Assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical.)
Express your answer using two significant figures.
we know that
K = Ae^(-Ea/RT)
ln K = lnA - (Ea/RT)
now
at two different conditions
ln K1 = lnA - (Ea1/RT)
lnA = lnK1 + (Ea1/RT)
and
ln K2 = ln A - (Ea2/RT)
ln A = lnK2 + (Ea2/RT)
so
we get
lnK1 + (Ea1/RT) = lnK2 + (Ea2/RT)
ln K2 - ln K1 = (Ea1/RT) - (Ea2/RT)
ln (K2/K1) = (Ea1 - Ea2)/RT
given
Ea1 = 122
Ea2 = 57
T = 25 C = 298 kelvin
so
ln (K2/K1) = (122-57) x 1000 / 8.314 x 298
(K2/K1) = 2.4767 x 10^11
so
the rate rate will increase by a factor of 2.4767 x 10^11
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