Question
In a constant pressure calorimeter, 55 mL of .320 M Ba(OH02 was added to 55 mL...
In a constant pressure calorimeter, 55 mL of .320 M Ba(OH02 was added to 55 mL of .640 M HCL. The run caused the temperature of the solution to rise from 22.13 to 26.49C. If the solution has the same density and specific heat as water, what is heat absorbed by the solution? Assume total volume is the sum of the individiual volumes. Q= _________ kJ
Homework Answers
Answer #1
Total volume of solution = 55ml + 55ml = 110ml
density of water = 1g/ml
mass of solution = volume * density
= 110*1 = 110g
Q = mC
T
= 110*4.184*(26.49-22.13) = 2006.6464J
Ba(OH)2 + 2HCl---------------> BaCl2 + 2H2O
1 mole of Ba(OH)2 gives 2 moles of H2O
0.0176moles of Ba(OH)2 gives = 2*0.0176 = 0.0352 moles of H2O
Q = 2006.6464/0.0352 = 57007J/mole = 57.007Kj/mole
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