Suppose we dissolve 12.5 g of a chiral compound in 0.2L of solution and place it in a tube that is 20.00 cm long. What is the samples' specific rotation if the observed rotation os experimentally determined to be 4 degrees
specific rotation = observed rotation/l*c
conc c= 12.5/200 = 0.0625g/ml
length l = 20cm = 2dm
specific rotation = observed rotation/l*c
= 4/2*0.0625
= 4/0.125
= 320 >>>> answer
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