Question

Suppose we dissolve 12.5 g of a chiral compound in 0.2L of solution and place it...

Suppose we dissolve 12.5 g of a chiral compound in 0.2L of solution and place it in a tube that is 20.00 cm long. What is the samples' specific rotation if the observed rotation os experimentally determined to be 4 degrees

Homework Answers

Answer #1

specific rotation = observed rotation/l*c

   conc c=       12.5/200 = 0.0625g/ml

   length l = 20cm = 2dm

   specific rotation = observed rotation/l*c

                                = 4/2*0.0625

                                 = 4/0.125

                                = 320 >>>> answer

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