Question

A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the...

A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 15.0 mL of HNO3.

Homework Answers

Answer #1

Given:

M(HNO3) = 0.5 M

V(HNO3) = 15 mL

M(NH3) = 0.2 M

V(NH3) = 75 mL

mol(HNO3) = M(HNO3) * V(HNO3)

mol(HNO3) = 0.5 M * 15 mL = 7.5 mmol

mol(NH3) = M(NH3) * V(NH3)

mol(NH3) = 0.2 M * 75 mL = 15 mmol

We have:

mol(HNO3) = 7.5 mmol

mol(NH3) = 15 mmol

7.5 mmol of both will react

excess NH3 remaining = 7.5 mmol

Volume of Solution = 15 + 75 = 90 mL

[NH3] = 7.5 mmol/90 mL = 0.0833 M

[NH4+] = 7.5 mmol/90 mL = 0.0833 M

They form basic buffer

base is NH3

conjugate acid is NH4+

Kb = 1.8*10^-5

pKb = - log (Kb)

= - log(1.8*10^-5)

= 4.745

use:

pOH = pKb + log {[conjugate acid]/[base]}

= 4.745+ log {8.333*10^-2/8.333*10^-2}

= 4.745

use:

PH = 14 - pOH

= 14 - 4.7447

= 9.2553

Answer: 9.26

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the...
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 25.0 mL of HNO3.
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the...
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 13.0 mL of HNO3.
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the...
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 23.0 mL of HNO3. Express your answer numerically.
A 50.0 mL sample of 0.150 M ammonia (NH3, Kb=1.8×10−5) is titrated with 0.150 M HNO3....
A 50.0 mL sample of 0.150 M ammonia (NH3, Kb=1.8×10−5) is titrated with 0.150 M HNO3. Calculate the pH after the addition of each of the following volumes of acid. A. 0.0 mL B. 25.0 mL C. 50.0 mL
A 25.0 mL sample of .100 M NH3 (Kb = 1.8 x 10^-5) was titrated with...
A 25.0 mL sample of .100 M NH3 (Kb = 1.8 x 10^-5) was titrated with .200 M HCl. Calculate the pH after addition of: a. 0.00 b. 6.25 c. 9.50 d. 12.5 e. 15.0 If I asked to many questions, please just post for c.
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the...
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the pH of the solution after the addition of 100.0 mL of HNO3. The Kb of NH3 is 1.8 × 10^-5.
4 A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine...
4 A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the pH of the solution after the addition of 100.0 mL of HNO3. The Kb of NH3 is 1.8 × 10-5. 8.72 6.58 3.44 10.56 5.28
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the...
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the pH of the solution after the addition of 100.0 mL of HNO3. The Kb of NH3 is 1.8 × 10-5. Please show work. a) 10.56 b) 5.28 c) 6.58 d) 8.72 e) 3.44
75.0 ml sample of 0.200 M sodium hydroxide is titrated with .200 M nitric acid. calculate...
75.0 ml sample of 0.200 M sodium hydroxide is titrated with .200 M nitric acid. calculate ph A) after adding 40.00 mL of HNO3 B) at the equivalent point
An 80.0 mL sample of 0.200 M ammonia is titrated with 0.100M hydrochloric acid. Kb for...
An 80.0 mL sample of 0.200 M ammonia is titrated with 0.100M hydrochloric acid. Kb for ammonia is 1.8 x 10-5. Calculate the pH of the solution at each of the following points of the titration: a. before the addition of any HCl. ______________ b. halfway to the equivalence point.______________ c. at the equivalence point._________________ d. after the addition of 175 mL of 0.100M HCl.____________
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT