A particular microwave oven delivers 750 watts (exact value). (A watt is a unit of power, which is the joules of energy delivered, or used, per second.) If the oven uses microwave radiation with a wavelength of 12.6 cm, how many photons of this radiation are required to heat 1.00 g of water by 1.00 °C, assuming that all of the photons are absorbed? The specific heat of water is 4.184 J / g•°C at 25°C.
1) determine the Joules of energy necessary to heat the water:
q = (mass) Δt) (Cp)
q = (1.0 g) (1 °C) (4.184 J g-1 °C-1)
q = 4.184 J
2) to determine how many Joules are carried by one photon of wavelength 12.6 cm:
Using λν = c and E = hν,
(12.6 cm) (ν) = 3.00 x 1010 cm s-1
ν = 2.381 x 109 s-1
E = (6.626 x 10-34 J s) (2.381 x 109 s-1)
E = 1.578 x 10-24 J per photon
3) Determination of moles of photons required:
4.814 J / 1.578x 10-24 J per photon = 3.0507 x 1024 photons
3.0507 x 1024 photons / 6.022 x 1023 photons mol-1 = 5.066 moles of photons
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