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At 775 Celsius, the equilibrium constant Kp for the synthesis of ammonia (below) is 3.35 *10^-5....

At 775 Celsius, the equilibrium constant Kp for the synthesis of ammonia (below) is 3.35 *10^-5. what is the value of Kc?

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Answer #1

Answer – We are given the Kp = 3.35*10-5 , T = 775+273 = 1048

N2 + 3 H2 ---> NH3

So, ∆n = sum of moles of product – sum of moles of reactant

           = 2 – 4

           = -2

We know formula

Kp = Kc *(RT)∆n

3.35*10-5 = Kc * (0.0821 *1048 )-2

3.35*10-5 = Kc * 0.000135

So, Kc = 3.35*10-5 / 0.000135

            = 0.248

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