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when 2.00g (0.0200 mole) of KHCO3 is mixed with 30.0 ml of the same hcl the...

when 2.00g (0.0200 mole) of KHCO3 is mixed with 30.0 ml of the same hcl the temp falls by 3.7 C. write a balanced equation for this reaction? b) calculate the enthalpy (delta h) of this reaction per mole of KHCO3?

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Answer #1

KHCO3 (s)+ HCl (aq) >> H2O (l)+ CO2(g) +KCl (aq)

Assuming the solution to be having same specific heat as that of water, (Cp=4.18 j/g.deg.c)

Density is assumed to be same as that of water (1gm/cc), mass of the solution = 30gm

Enthalpy change= mass*specific heat* temperature difference = -30*4.18*3.7=-463.98 joule

2 gm of KHCO3 correspond to =2/100 moles= 0.02 moles ( Molecular weight of KHCO3=100)

0.02 moles required 463.98 joules

1 mole required 463.98/0.02=23199 joules/mole = 23.199 Kj/mol

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