What is the theoretical yield of hexanol from this experiment? (1-hexene density = .673 g/mL) The experiment is converting 1-hexene to 2-hexanol by acid-catalyzed hydration.
Theoretical yield:
It is expressed in terms of moles / mass of the product formed from the limiting reactant.
Here mole ratio between hexanol to hexene is 1 :1 ,
So we can calculate the moles of product ( hexanol ) by using moles of 1-hexene
Calculation of moles of 1 –hexane
= Mass of hexane / molar mass of hexane
Lets assume 1mL of the hexane used.
Moles of hexane = (1.0 mL x 0.673 g / mL) / 86.18 g per mol
=0.007809
Moles of hexanol = moles of hexane = 0.007809 mol
Mass of hexanol = mole x molar mass = 0.007809x 102.17 g /mol
= 0.798 g
Therefor theoretical yield of hexanol = 0.798 g , when we use 1.0 mL hexane
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