Question

The rate constant for a particular reaction is 1.04 x 104 at 21.8°C and is 6.63...

The rate constant for a particular reaction is 1.04 x 104 at 21.8°C and is 6.63 x 104 at 93.5°C. What is the activation energy for the reaction, in kJ/mol? R = 8.314472 J/mol·K.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Use the Arrhenius equation to do so:

K = Ae(-Ea/RT)

lnK = lnA - Ea/RT

This would be the equation to use. Now, as we are having two rates at two differents temperatures we have:

lnK1 = lnA - Ea/RT1 and lnK2 = lnA - Ea/RT2 dividing these two equations we have:

ln(K1/K2) = Ea/R (1/T2 - 1/T1) and from here we solve for Ea:

T1 = 21.8 + 273 = 294.8 K; T2 = 93.5 + 273 = 366.5 K

ln (1.04x104/6.63x104) = (Ea/8.3144) (1/366.5 - 1/294.8)

-1.852384 = (Ea/8.3144) (-6.6701x10-4)

Ea = 1.852384 * 8.3144 / 6.6701x10-4

Ea = 23088.12 J/mol

Ea = 23088.12 / 1000 = 23.09 kJ/mol

Hope this helps

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The activation energy, Ea for a particular reaction is 13.6 kj/mol. If the rate constant at...
The activation energy, Ea for a particular reaction is 13.6 kj/mol. If the rate constant at 754 degrees celsius is 24.5/min at egat temperature in celsius will the rate constant be 12.7/min? r= 8.314j/mol • K
For the reaction A + B C, the rate constant at 215 oC is 5.0 x...
For the reaction A + B C, the rate constant at 215 oC is 5.0 x 10-3 and the rate constant at 452o C is 1.2 x 10-1.             a) What is the activation energy in kJ/mol?             b) What is the rate constant at 100o C.
For the reaction A + B-> C, the rate constant at 315 oC is 5.0 x...
For the reaction A + B-> C, the rate constant at 315 oC is 5.0 x 10-3 and the rate constant at 652o C is 1.2 x 10-1. a) What is the activation energy in kJ/mol? b) What is the rate constant at 100o C Please show work.
For a particular reaction at 221.9 °C, ΔG = -92.39 kJ/mol, and ΔS = 130.33 J/(mol·K)....
For a particular reaction at 221.9 °C, ΔG = -92.39 kJ/mol, and ΔS = 130.33 J/(mol·K). Calculate ΔG for this reaction at -54.3 °C. ____________ kJ/mol
For a particular reaction at 128.1 °C, ΔG = 377.52 kJ/mol, and ΔS = 556.72 J/(mol·K)....
For a particular reaction at 128.1 °C, ΔG = 377.52 kJ/mol, and ΔS = 556.72 J/(mol·K). Calculate ΔG for this reaction at -78.3 °C. = ? kJ / mol
For a particular reaction at 188.9 °C, ΔG = 287.40 kJ/mol, and ΔS = 811.42 J/(mol·K)....
For a particular reaction at 188.9 °C, ΔG = 287.40 kJ/mol, and ΔS = 811.42 J/(mol·K). Calculate ΔG for this reaction at 4.1 °C.
For a particular reaction at 152.8 °C, ΔG = -966.13 kJ/mol, and ΔS = 459.28 J/(mol·K)....
For a particular reaction at 152.8 °C, ΔG = -966.13 kJ/mol, and ΔS = 459.28 J/(mol·K). Calculate ΔG for this reaction at -54.9 °C.
For a particular reaction at 132.0 °C, ΔG = 496.12 kJ/mol, and ΔS = 302.61 J/(mol·K)....
For a particular reaction at 132.0 °C, ΔG = 496.12 kJ/mol, and ΔS = 302.61 J/(mol·K). Calculate ΔG for this reaction at 0.4 °C.
For a particular reaction at 111.6 °C, ΔG = 131.35 kJ/mol, and ΔS = 201.60 J/(mol·K)....
For a particular reaction at 111.6 °C, ΔG = 131.35 kJ/mol, and ΔS = 201.60 J/(mol·K). Calculate ΔG for this reaction at -25.3 °C.
If the rate constant for a particular reaction doubles between 20 °C and 40 °C, calculate...
If the rate constant for a particular reaction doubles between 20 °C and 40 °C, calculate the value of the activation energy for the reaction.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT