Question

# 12. The combustion of liquid chloroethylene, C2H3Cl, yields carbon dioxide, steam, and hydrogen chloride gas. a....

12. The combustion of liquid chloroethylene, C2H3Cl, yields carbon dioxide, steam, and hydrogen chloride gas.

a. Write a balanced equation for the reaction

. b. How many moles of oxygen are required to react with 35.00 g of chloroethylene?

c. If 25.00 g of chloroethylene react with an excess amount of oxygen, how many grams of each product are formed?

Could someone help me with this question thanks!

a) The balanced reaction is given below b) 1 mole of chloroethylene reacts with 2.5 moles of oxygen

Molar mass of chloroethylene = 2 * 12 + 3 * 1 + 35.5 = 62.5 gm/mol

Number of moles of chloroethylene = 35/62.5 = 0.56 moles

Moles of O2 gas = 2.5 * 0.56 = 1.4 moles

c) Number of moles of chloroethylene = 25/62.5 = 0.4

Moles of CO2 formed = 2 * 0.4 = 0.8 moles

Moles of H2O formed = Moles of HCl formed = 0.4 moles

Mass of CO2 formed = 0.8 * 44 = 35.2 gms

Mass of H2O formed = 0.4 * 18 = 7.2 gms

Mass of HCl formed = 0.4 * 36.5 = 14.6 gms

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