A solution is made by dissolving 5.4893g of CsSO4 in sufficient water to form exactly 100.00mL soultion. Identify the solute and the solvent, Find the number of moles of solute in the solution. Determine the molarity of the solution.
Solute is the component which is present in less amount in a solution and the solvent is the component present in higher amount in a solution.
In the given solution, CsSO4 is solute and water is solvent.
No.of moles of solute = mass / molar mass = 5.4893 / 228.96 = 0.02397 mol
Volume of the solution = 100 mL = 0.1 L
Molarity = no.of moles of solute / volume of the solution (L)
Molarity = 0.02397 / 0.1 = 0.2397 M <<<<<<--------(ANSWER)
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