Question

The pKa of hydrocyanic acid, HCN, is 9.218 at 293 K. Calculate the conductivity of an...

The pKa of hydrocyanic acid, HCN, is 9.218 at 293 K. Calculate the conductivity of an aqueous solution of perchloric acid, of concentration 0.015 mol dm-3, given that the ionic conductivity of H+ ions is 35 mS m2 mol-1 and of CN- ions is 82 mS m2 mol-1

Homework Answers

Answer #1

Values:

Formulas:

Limit molar conductivity ():

molar conductivity ():

Process:

First: Define limit molar conductivity.

Second: Define molar conductivity

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the initial concentration of an aqueous solution of the weak acid, hydrocyanic acid (HCN), with...
Calculate the initial concentration of an aqueous solution of the weak acid, hydrocyanic acid (HCN), with a pH of 6.4. The pKa of hydrocyanic acid is 9.31.
The pH at 25 °C of an aqueous solution of the sodium salt of hydrocyanic acid...
The pH at 25 °C of an aqueous solution of the sodium salt of hydrocyanic acid (NaCN) is 11.14. Calculate the concentration of CN- in this solution, in moles per liter. Ka for HCN is equal to 6.2×10-10.
To learn how to calculate ion concentrations in an aqueous solution of a strong diprotic acid....
To learn how to calculate ion concentrations in an aqueous solution of a strong diprotic acid. Sulfuric acid, H2SO4, is a strong acid. Its complete dissociation in aqueous solution is represented as H2SO4?H++HSO4? A HSO4? anion can dissociate further by HSO4??H++SO42? but the extent of dissociation is considerably less than 100%. The equilibrium constant for the second dissociation step is expressed as Ka2=[H+][SO42?][HSO4?]=0.012 Part A Calculate the concentration of H+ ions in a 0.010 M aqueous solution of sulfuric acid....
To learn how to calculate ion concentrations in an aqueous solution of a strong diprotic acid....
To learn how to calculate ion concentrations in an aqueous solution of a strong diprotic acid. Sulfuric acid, H2SO4, is a strong acid. Its complete dissociation in aqueous solution is represented as H2SO4?H++HSO4? A HSO4? anion can dissociate further by HSO4??H++SO42? but the extent of dissociation is considerably less than 100%. The equilibrium constant for the second dissociation step is expressed as Ka2=[H+][SO42?][HSO4?]=0.012 Part A Calculate the concentration of H+ ions in a 0.010 M aqueous solution of sulfuric acid....
The limiting molar ionic conductivities for Mg2+ and Cl- are 0.0106 Ω-1 mol-1 m2 and 0.0076...
The limiting molar ionic conductivities for Mg2+ and Cl- are 0.0106 Ω-1 mol-1 m2 and 0.0076 Ω-1 mol-1 m2 respectively. a) Calculate the limiting molar conductivity of an MgCl2 solution (2 marks). b) Calculate the ionic mobility (2 marks), ionic conductivity (2 marks) and transport number (2 marks) for the magnesium and chloride ions in a 0.01 M MgCl2 solution. c) What electric field strength would produce a current density of 1 mA cm-2 for this 0.01 M solution of...
1). Consider a 0.4 M solution of   anilinium chloride. The ion   anilinium is the conjugate acid...
1). Consider a 0.4 M solution of   anilinium chloride. The ion   anilinium is the conjugate acid of the the weak base aniline.The pKb   of aniline is 9.13   Part a).   Calculate  [H+] __________ M Part b). Calculate the concentration of   anilinium ions. __________ M Part c). Calculate the concentration of   aniline in equilibrium. _________ M Part d). Calculate [OH−] ________ M Part e). Calculate [Cl-] ________ M Part f). Calculate the pH _______ M 2). Calculate the pH and the concentration [Na+] =of all...
Consider a 2×10−2 M  solution of the weak acid butanoic acid , for which pKa =  4.83 ....
Consider a 2×10−2 M  solution of the weak acid butanoic acid , for which pKa =  4.83 . You can search for the structure of this compound online, although precise knowledge of the structure is not needed. Your answers need to be within 5% of the correct answer to be considered correct. Don't round or you will fall outside the 5% margin of error. Part A: Calculate  [H+] (units in M) Part B: Calculate the concentration of butanoate ions (units in M) Part...
Given the pKa of acetic acid to be 4.75. Calculate the pH of a buffer that...
Given the pKa of acetic acid to be 4.75. Calculate the pH of a buffer that is comprised of 50.0 mL of 0.18 M acetic acid and 75.0 mL of 0.15 M sodium acetate. THEN you add 15.0 mL of 0.03 M HCl to the buffer solution described. What are the [H+] and pH after the mixture reaches equilibrium?
1.074 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in...
1.074 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in 54.37 mL of water. 22.02 mL of HCl is added to the solution, resulting in a pH of 6.78. Calculate the concentration of the HCl solution. The pKa of ACES is 6.85.
1.151 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in...
1.151 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in 77.41 mL of water. 21.00 mL of HCl is added to the solution, resulting in a pH of 6.83. Calculate the concentration of the HCl solution. The pKa of ACES is 6.85.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT