The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be produced from 7.15g of butanoic acid and excess ethanol?
molar mass of butyrate = 116.16 gram/mol
molar mass of butanoic acid = 88.11 gram/mol
theriticallly 88.18 grams of butanoic acid will give 116.16 grams of butyrate
7.15 grams of butanoic acid will give how much
7.15 x 116.16 / 88.18
= 9.148 grams should get this is theritical yield
but actually 78.0% is the yield
actuall yield / theritical yield x 1000 = 78.0
actul yield = 78.1 x theritical yield / 100
= 78.1 x 9..148 / 100
= 7.35 grams butyrate will produce
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