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Part A: The activation energy of a certain reaction is 42.8 kJ/mol . At 28 ∘C...

Part A:

The activation energy of a certain reaction is 42.8 kJ/mol . At 28 ∘C , the rate constant is 0.0190s−1. At what temperature in degrees Celsius would this reaction go twice as fast?

Part B:

Given that the initial rate constant is 0.0190s−1 at an initial temperature of 28  ∘C , what would the rate constant be at a temperature of 150  ∘C for the same reaction described in Part A?

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