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Oxalic acid (H2C2O4) is a diprotic acid. How many milliliters of 0.1897 M NaOH is required...

Oxalic acid (H2C2O4) is a diprotic acid. How many milliliters of 0.1897 M NaOH is required to neutralize 0.3442 L of 0.2456 M oxalic acid? [Hint: 2 moles of NaOH would react with 1 mole of oxalic acid.]

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Answer #1

The reaction between oxalic acid and sodium hydroxide is

FOR THE NUTRALIZATION REACTIONS THE RELATION BETWEEN THE MOLARITY AND VOLUME IS

WHERE M1 = MOLARITY OF H2C2O4 M2 = MOLARITY OF NaOH

V1 = VOLUME OF H2C2O4 V2 = VOLUME OF NaOH

n1,n2 are stiochiometric quoefficints in neutralization reaction.

now let us find out volume of NaOH in Litres ,then we can convert into millilires .

so the volume of NaOH required to neutralize H2C2O4 is 891.25 milllit.

  

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