Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3). What mass of ammonium phosphate is produced by the reaction of 6.2 of ammonia? Round your answer to significant digits.
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass of NH3 = 6.2 g
mol of NH3 = (mass)/(molar mass)
= 6.2/17.03
= 0.364 mol
Balanced chemical equation is:
3NH3 + H3PO4 —> (NH4)3PO4
According to balanced equation
mol of (NH4)3PO4 formed = (1/3)* moles of NH3
= (1/3)*0.364
= 0.1213 mol
Molar mass of (NH4)3PO4,
MM = 3*MM(N) + 12*MM(H) + 1*MM(P) + 4*MM(O)
= 3*14.01 + 12*1.008 + 1*30.97 + 4*16.0
= 149.096 g/mol
mass of (NH4)3PO4 = number of mol * molar mass
= 0.1213*1.491*10^2
= 18.09 g
Answer: 18 g
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