Question

Following the general procedure described in this experiment , a student synthesized 6.895 g of barium idoate monhydrate, Ba(IO3)2 . H2), by adding 30.00 mL of 5.912x10^(-1) M barium nitrate, Ba(NO3)2, to 50.00 mL of 9.004x10^(-1) M sodium idoate, NaIO3.

When reviewing the procedure and calculations, the student discovered that a 4.912x10^(-1) M barium nitrate solution had been used instead of a 5.912x10^(-1) M solution.

Calculate the precent yield of barium iodate monhydrate using 30.00 mL of 4.912x10^(-1) M barium nitrate solution and 50.00 mL of 9.004x10^(-1) M sodium iodate solution.

(4) Calculate the precent error in the precent yield calculated in (2) compared with the correct precent yield calculated in (3)

Answer 1