Question

For which .10M diprotic acid would the 2nd dissociation affect the pH significantly? Explain. H2A: Ka1=4.2*10^-2...

For which .10M diprotic acid would the 2nd dissociation affect the pH significantly? Explain.

H2A: Ka1=4.2*10^-2 Ka2=1.8*10^-7

H2B: Ka1=2.4*10^-4 Ka2= 6.1*10^-8

H2C: Ka1=1.3*10^-4 Ka2=5.2*10^-9

H2D: Ka1=1.8*10-3 Ka2=9.3*10^-4

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