An aqueous solution containing 17.5 g of an unknown molecule (non electrolyte) compound in 100 g water has a freezing point of -1.8 degrees Celsius. Calculate the molar mass of the unknown compound.
For water, Kf =
-1.87 oC Kg/mol
17.5 g solute present in 100 g water
=> In 1000g water, 175 g solute present
Molality, m = (temperature difference/Kf ) =
T /
Kf =
(-1.8-0)/-1.87 = 3.366 m
Molality is the miles of solute in 1000g of solvent
=> number of moles/1000 g water = weight of solute in 1000gm water/molar mass of compound = 3.366 m
=> molar mass of compound = 175/3.366 = 51.99 g/mol
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