Question

Assuming 100% dissociation, calculate the freezing point and boiling point of 1.99 m AgNO3(aq). Constants may be found here.

Answer #1

[AgNO3]= 1.99 m , we know m is molality which is equal to = mol of solute / Mass of solute in kg.

Since the dissociation is 100 % so the i ( number of particles that are formed in the solution ) = 2

Solution:

We use following formulae.

Delta Tf = i x m x kf

Here I = 2 , m is molality, kf is the freezing point constant of water.

Delta Tf = freezing pint of the solvent – freezing point of the
solution = 0^{0} C – (freezing point of the solution)

Kf of water = -1.86 ^{0}C/ m

Lets plug the given values.

-(freezing point of the solution) = 2 x 1.99 m x ( -1.86
^{0}C/m)

**Freezing point of the solution =- 7.40
^{0}C**

Assuming 100% dissociation, calculate the freezing point and
boiling point of 2.99 m AgNO3(aq). Constants may be found here.
Solvent
Formula
Kf
value*
(°C/m)
Normal freezing
point (°C)
Kb
value
(°C/m)
Normal boiling
point
(°C)
water
H2O
1.86
0.00
0.512
100.00
benzene
C6H6
5.12
5.49
2.53
80.1
cyclohexane
C6H12
20.8
6.59
2.92
80.7
ethanol
C2H6O
1.99
–117.3
1.22
78.4
carbon
tetrachloride
CCl4
29.8
–22.9
5.03
76.8
camphor
C10H16O
37.8
176

Assuming 100% dissociation, calculate the freezing point and
boiling point of 2.19 m Na2SO4(aq). Constants may be found
here.

Assuming 100% dissociation, calculate the freezing point and
boiling point of 1.52 m SnCl4(aq). Constants may be found here.
vent
Formula
Kf
value*
(°C/m)
Normal freezing
point (°C)
Kb
value
(°C/m)
Normal boiling
point
(°C)
water
H2O
1.86
0.00
0.512
100.00
benzene
C6H6
5.12
5.49
2.53
80.1
cyclohexane
C6H12
20.8
6.59
2.92
80.7
ethanol
C2H6O
1.99
–117.3
1.22
78.4
carbon
tetrachloride
CCl4
29.8
–22.9
5.03
76.8
camphor
C10H16O
37.8
176

Assuming 100% dissociation, calculate the freezing point and
boiling point of 3.37 m AgNO3(aq).

Assuming 100%
dissociation, calculate the freezing point (TfTf) and boiling point
(TbTb) of 1.92 m SnCl4(aq)1.92 m SnCl4(aq).
Colligative constants
can be found in the chempendix.

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Constants for freezing-point depression and boiling-point
elevation calculations at 1 atm:
Solvent
Formula
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(°C/m)
Normal freezing
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Kb value
(°C/m)
Normal boiling
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(°C)
water
H2O
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benzene
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80.1
cyclohexane
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ethanol
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carbon
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