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Assuming you combined 250 g Na2CO3 and 360.0 g AgNO3, calculate the expected yield of solid...

Assuming you combined 250 g Na2CO3 and 360.0 g AgNO3, calculate the expected yield of solid Ag2CO3. What is the Limiting Reagent in this reaction? What is the percent yield?

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Answer #1

Molar mass of Na2CO3 = 23 * 2 + 12 + 16 * 3 = 106 gm/mol

Number of moles of Na2CO3 = mass/molar mass = 250/106 = 2.3584 moles

Molar mass of AgNO3 = 1 * 107.8 + 14 + 3 * 16 = 169.8 gm/mol

Number of moles of AgNO3 = mass/molar mass = 360/169.8 = 2.120 moles

1 mole of Na2CO3 will react with 2 mole of AgNO3, hence AgNO3 is the limiting reagent

2 moles of AgNO3 will produce one mole of Ag2CO3

Moles of Ag2CO3 produced = 2.120/2 = 1.060 moles

Molar mass of Ag2CO3 = 107.8 * 2 + 12 + 16 * 3 = 275.6 gm/mol

Mass of Ag2CO3 produced = molar mass * number of moles = 1.060 moles * 275.6 gm/mol = 292.136 gms

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