calculate the pH of the following solutions. A) a solution that is 0.240 M in sodium formate (HCOONa) and 0.120 M in formic acid (HCOOH). B) a solution that is made by combining 55 mL of 6.0×10?2 M hydrofluoric acid with 125 mL of 0.12 M sodium fluoride.
Apply the hendersson hasselbach equation, the pka of formic acid is 3.75 (i found it on the web)
PH = PKa + log [Base]/[Acid]
PH = PKa + log [HCOO-] / [ HCOOH ]
PH = 3.75 + log [0.24 / 0.12] = 4.05
b)
Calculate the new molarities
moles of HF = molarity * volume = 0.055 * 0.06 = 0.0033 moles
total volume = 55 + 125 = 180 ml = 0.18 L
Molarity of HF = 0.0033 / 0.18 = 0.01833 M
moles of NaF = molarity * volume = 0.12 * 0.125 = 0.015 moles
molarity NaF = 0.015 / 0.18 = 0.0833 M
PH = PKa + log [Base]/[Acid]
PH = PKa + log [F-] / [ HF ] ; pka of HF = 3.17
PH = 3.17 + log [0.0833 / 0.01833] = 3.82
*hope this helps =)
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