Question

What is the maximum mass of H20 that can be produced by combining 52.0 g of each reactant?

4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(G)

Answer 1

Molecular mass of NH3=14+3*1=17u

Molecular mass of O2=16*2=32u

According to chemical equation

(4*17)68g of ammonia react with (5*32)160 g of Oxygen to form 108g(6*18) of H2O

Oxygen is a limiting reagent because it is required in large amount in comparison to Ammonia.

So yield depend on limiting reagent.

Mass of H2O=(Mass of H2O in reaction*Mass of Limiting Reagent taken)/Mass of Limiting Reagent Reaction/

Mass of H2O formed=108*52/160=35.1 g of water will produced.

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