Question

Assuming a one to one stoichiometry, starting with 8.93 mL of 2-methylpropan-2-ol, how many grams of 2-chloro-2-methylpropane should be produced? This is called the theoretical yield. Round to three significant figures. Assuming the molecular weight of 2-chloro-2-methylpropane is 92.5, and the molecular weight of 2-methylpropan-2-ol is 74.

Answer #1

density of 2-methylpropan-2-ol = 0.781

Density = mass/volume

mass of 2-methylpropan-2-ol = density x volume = 0.781 x 8.93 = 6.974 grams

1 mole of 2-methylpropan-2-ol will produce 1 mole of 2-chloro-2-methylpropane

no. of moles of 2-methylpropan-2-ol = 6.974 / 74 = 0.09425 moles

0.09425 moles of 2-methylpropan-2-ol will produce 2-chloro-2-methylpropane = 0.09425 moles

Weight of (theoretical yield) 2-chloro-2-methylpropane formed =
0.09425 x 92.5 = **8.718 grams**

Using information from previous questions and assuming a one to
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Part A) What is the molecular formula (hillmethod) of
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