Question

A dilute aqueous solution has a density of 0.9992474 g/mL at 14°C and a density of 0.9965162 g/mL at 27°C. a) Calculate the percentage expansion in volume when the solution is heated from 14° to 27°C. (b) If the solution has a measured concentration of 0.4559 M at 14°C, what will its concentration be at 27°C?

Answer 1

let us take 10 ml smaple at 14 C

at 14 C , mass of sample = d*v = 0.9992474*10 = 9.992474 g

at 27 C , there is no change in mass, but there may be change in volume.

               volume of sample = m/d = 9.992474 /0.9965162 = 10.027407 ml

a) percentage expansion in volume = (10.027407-10)/10*100 = 0.2741%

b)     M1V1 = M2V2

          (0.4559*10 = M2*10.027407)

    M2 = conventration at 27 c = 0.454654 M