Question

# Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with...

Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium sulfite:

MnO4−(aq)+SO32−(aq)→MnO2(s)+SO42−(aq)

Since this reaction takes place in basic solution, H2O(l) and OH−(aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation:

MnO4−(aq)+SO32−(aq)+     −−−→MnO2(s)+SO42−(aq)+     −−−

Part B

What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(l) and OH−(aq) in the blanks where appropriate. Your answer should have six terms.

Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes.

#### Homework Answers

Answer #1

Balance the reaction in basic solution

so

split reaction

MnO4− --> MnO2

SO3-2 --> SO4-2

balance O adding H2O

MnO4− --> MnO2 + 2H2O

H2O + SO3-2 --> SO4-2

Balance H adding H+

4H+ + MnO4− --> MnO2 + 2H2O

H2O + SO3-2 --> SO4-2 + 2H+

blance charges

3e- + 4H+ + MnO4− --> MnO2 + 2H2O

H2O + SO3-2 --> SO4-2 + 2H+ + 2e-

balance e-

6e- + 8H+ + 2MnO4− --> 2MnO2 + 4H2O

3H2O + 3SO3-2 --> 3SO4-2 + 6H+ + 6e-

add all

6e- + 8H+ + 2MnO4− + 3H2O + 3SO3-2 --> 3SO4-2 + 6H+ + 6e- + 2MnO2 + 4H2O

cancel common terms

2H+ + 2MnO4−+ 3SO3-2 --> 3SO4-2 + 2MnO2 + H2O

add OH- to make it basic

2OH- + 2H+ + 2MnO4−+ 3SO3-2 --> 3SO4-2 + 2MnO2 + H2O + 2OH-

convert to water

2H2O + + 2MnO4−+ 3SO3-2 --> 3SO4-2 + 2MnO2 + H2O + 2OH-

cancel water

H2O + + 2MnO4−+ 3SO3-2 --> 3SO4-2 + 2MnO2 + 2OH-

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