Calculate the concentrations of all species in a 1.23 M Na2SO3 (sodium sulfite) solution. The ionization constants for sulfurous acid are Ka1 = 1.4× 10–2 and Ka2 = 6.3× 10–8.
First you need to calculate the final pH
Since you are adding the conjugate base lets do de analysis as a base:
the mass action equation, remember since it is for the base is Kb and
At the equilibrium the concentration of the OH is equal to HSO3-
X=[OH]
C0=concentration added
Solving for X you get a quadratic equation that can be solved:
X=4.36x10-4=OH
Remember
so H+=2.29x10-11
pH=10.64
Now using both mass action equations you can find the concentrations of the other compounds:
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