A .438 g of sample of a compound containing only C and H is combusted in oxygen producing 1.481 g of CO2 and .303 g of H2O. What is the empirical formula of the compound?
Answer -
We have work backward. You know the formula for combustion.
combustion of the hydrocarbon.
Compound + O2 = CO2 + H2O
mols of H2O = 0.303 / (1*2+16) = 0.01683 mols
mols of CO2 = 1.481 / (12+16*2) = 0.03366 mols
Divided by smaller number of moles to got a whole number.
0.03366 / 0.01683 = 2
ratio of H2O : CO2 is 1
: 2
ratio of H2O :
H is 1 : 2
therefore, ratio of C : H is 1 :
1
Empirical formula: CH
Hence, the empirical formula of the compund is CH.
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