Question

The vapor pressure of water is 0.2561 psi at 60F and 0.3629 psi at 70F. A....

The vapor pressure of water is 0.2561 psi at 60F and 0.3629 psi at 70F.
A. Estimate it's heat of vaporization over the temp range (Ans: 49.2 kJ)
B. One day, the weatherman reported the temperature and relative humidity to be 70F and 75% respectively. Use your result from A to estimate the dew point on that day (the temp at which water vapor condenses into liquid).
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Answer #1

(A) Given temperature, T1 = 60 F = 288.7 K, vapor pressure, P1 = 0.2561 psi

temperature, T2 = 70 F = 294.26 K, vapor pressure, P2 = 0.3629 psi

Applying Vant hoff equation

ln(P2 / P1) = (Hv / R) x [1/T1 - 1/T2]

=> ln(0.3629 psi / 0.2561 psi) =  (Hv / 8.314 J.K-1mol-1) x [1/288.7K - 1/294.26K]

=> 0.34856 = (Hv / 8.314 J.K-1mol-1) x [5.56K / 288.7K x 294.26K]

=> Hv = (0.34856 x 8.314 J.K-1mol-1 x 288.7K x 294.26K) / 5.56K = 44.3 KJ (answer)

(B) Given ambient temperature = 70 F = 294.26 K

RH = 75 %

Dew point temperature can be calculated from the following formulae

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