Question

A photon with an energy of 98.9 keV excites and dislodges a tungsten K-shell electron, which then dislodges an L-shell electron. Calculate the released L-shell electron energy in [keV]. (Note: K-shell binding energy is 67.5 keV and the L-shell binding energy is 11 keV for Tungsten.)

Please explain and show steps

Answer 1

Energy of photon = 98.9 keV

Binding energy of K-hell = 67.5 keV

Binding energy of L-shell = 11 keV

Now, when the photon dislodges the tungsten K-shell electron:

Energy absorbed by the K-shell electron = Energy of photon - Binding energy of K-hell

= 98.9 - 67.5

= 31.4 keV

Now this K-shell electron dislodges an L-shell electron:

Released L-shell electron energy = Energy absorbed by the K-shell electron - Binding energy of L-shell

= 31.4 - 11

Released L-shell electron energy = 20.4 keV