If the conversion of 77.0% pure ferric oxide to iron and oxygen is 85.0% efficient, what mass of this ferric oxide is required to make 4.00 moles of iron?
molar mass of of Fe2O3 = 159.69 g/mole
Balancing equation 4 Fe + 3 O2 2 Fe2O3
to produce 4 moles of Iron we require 2 moles of Fe2O3
2 Fe2O3 = 2159.69
above value is taken as X.
Now we have to calculate the mass of the ferric oxide required to make 4 moles of Iron is 77% of 85% X
= 0.77 0.85 319.38
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