The atomic masses of 203Tl and 205Tl are 202.972336 and 204.974410 amu, respectively. The average atomic mass of thallium is 204.383 amu. Calculate the natural abundances of these two isotoped.
Percent abundance of 203Tl: ____%
Percent abundance of 205Tl: _____%
Assuming only the above mentioned isotopes exist in nature,,
Let x% be the abundance of 203Tl, then it is obvious that the abundance of 205Tl is 100-x%
The average atomic mass is the sum of individual atomic masses times their corresponding abundance.
Then we have,
202.972336 * x% +204.974410 * (100-x)% = 204.383
- 2.002074 x% + 204.9744410 = 204.383
0.591441/2.002074 = 0.2954
All measured in amu.
by solving for x we get, x = 0.2954 ie abundance of Li(6) is 29.54% aboundance of 203Tl
70.56 % aboundance of 205Tl
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