How many moles of carbon dioxide, CO2, are produced if 5.87 moles of glucose, C6H12O6, react?
C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l)
Moles of CO2 produced = 35.22 mol
Explanation
According to the given reaction
C6H12O6 (s) + 6 O2 (g) 6 CO2 (g) + 6 H2O (l)
one mole of glucose (C6H12O6) , when reacts with excess oxygen gas, produces six moles of carbon dioxide (CO2)
or we can say that , moles of CO2 produced = 6 * moles of glucose reacted
when moles of glucose = 5.87 mol,
then, moles of CO2 produced = 6 * (5.87 mol)
moles of CO2 produced = 35.22 mol
if moles of O2 are also specified, then answer might be different
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