Question

How much 5.60M NaOH must be added to 410.0 mL of a buffer that is 0.0205...

How much 5.60M NaOH must be added to 410.0 mL of a buffer that is 0.0205 M acetic acid and 0.0235 M sodium acetate to raise the pH to 5.75?

Homework Answers

Answer #1

Values:

Base: NaOH 5.60M x mL to rise pH buffer at 5.75 units

Buffer: CH3-COOH 0.0205M / CH3-COONa 0.0235M Vbuffer=410 mL

pKa: CH3-COOH 4.7

Process:

pH = pKa + Log10[Salt]/[Acid]

pH = 4.7 + Log10[0.0235M]/[0.0205M]

pH = 4.76

How much NaOH need to rise pH 4.76 to 5.75?

If: 410 mL Buffer + x mL NaOH ---------> pH=5.75; buffer aport 4.76 pH unit + 0.99 pH unit aport NaOH.

Then:

M1 x V2 = M2 x V1

-Log10M1 x V2 = -Log10M2 x V1

pH1 x V2 = pH2 x V1

4.76 x V2 = 5.75 x 410 mL

V2=(5.75 x 410 mL) / 4.76

V2=495.27 mL is the final volume to pH rise at 4.76 to 5.75, if the initial buffer volume is 410 mL the excess volume is 85.27 mL, this volume correspond at NaOH 5.60M

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