Question

Calculate DH for the reaction 2C(s) + H2(g)                 C2H2(g) given the following chemical equations and their...

Calculate DH for the reaction

2C(s) + H2(g)                 C2H2(g)

given the following chemical equations and their respective enthalpy changes:

C2H2(g) +    O2(g)                2CO2(g) + H2O DH = -1299.6kJ

       C(s) + O2(g)         CO2(g)                         DH = -393.5kJ

      H2(g) +    O2(g)              H2O(l)                     DH = -285.8kJ

Please help!!! I am completely lost! How do I start, what are the steps?

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Homework Answers

Answer #1

2CO2(g) + H2O(l) ----> C2H2(g) + 5/2O2(g)   DH = + 1299.6kJ

2C(s) + 2O2(g)   ---->    2CO2(g)                     DH = - 787kJ

H2(g) +    O2(g)   ----> H2O(l)                         DH = - 285.8kJ

By adding the above three equations

2C(s) + H2(g)   ----> C2H2(g)                  DH = + 226.8 KJ

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