Calculate the standard entropy change for the following reaction at 25 °C. S° 2CH3OH(g)+3O2(g)=2CO2(g)+4H2O(g)
2CH3OH(g)+3O2(g)=2CO2(g)+4H2O(g)
delta So (CH3OH) = 239.81 J/mol-K
delta So (O2) = 205.14 J/mol-K
delta So (CO2) = 213.74 J/mol-K
delta So (H2O) = 188.83 J/mol-K
delta So (Rxn) = 2*delta So (CO2) +4*delta So (H2O) -
2*delta So (CH3OH) - 3*delta So (O2)
= 2*213.74 + 4*188.83 - 2*239.81 - 3*205.14
= 87.76 J/mol-K
Answer: 87.76 J/mol-K
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