Question

Construct a Born-Haber cycle to calculate the lattice energy of MgCl2.

The *CRC Handbook of Chemistry and Physics* lists the
MgCl2 lattice energy as 2540 kJ mol-1. How does your answer compare
to the literature value?

Answer #1

**Heat of formation of MgCl2 = sublimation of Mg +First
Ionization energy of Mg + second ionization energy of Mg
+**

**
dissociation of Cl2 + 2 x electron affinity of Cl + Lattice energy
fo MgCl2**

**-641.1 KJ/mol = 150 + 737.7 + 1450.7 + 243 -2(348.57)
+Lattice energy of MgCl2**

**Lattice enrgy = -2525 KJ/mol**

**Thus we get value of 2525 KJ/mol compared to 2540
KJ/mol**

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Part B
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Na(s) → Na(g) ΔsubH = 107 kJ
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Na(s) + 1/2 F2(g) → NaF(s) ΔfH =
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Data:
Ag(g) Ag+(g) +
e-
7.576 eV
Br(g) + e-
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