Question

A 3.00-mL aliquot of 0.001 M, NaSCN is diluted to 25.0 mL with 0.2 M Fe(NO3)3...

A 3.00-mL aliquot of 0.001 M, NaSCN is diluted to 25.0 mL with 0.2 M Fe(NO3)3 and 0.1 M HNO3.

Homework Answers

Answer #1

M1 V1 = M2 V2

0.001*3 = M2*25

M2 = 0.003/25 = 0.00012M of SCN-

SCN- + Fe3+ ------->FenCS2+

1 mole scn-produces 1 mole of fencs2+

1 mole SCN- produces 1 mole of FeNCS2+

no of moles of FeNCS2+ = molarity * volume in L

                                   = 0.00012*0.025 = 3*10-6 moles

molesper liter   = 3*10-6 *1000/25 = 3*10-4 moles/liter

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