Question

A copper refinery produces a copper ingot weighing 82.3kg. The density of copper is 8.94g/cm³

a) If the copper is drawn into a wire whose diameter is 7.25mm, how many feet of copper can be obtained from the ingot? ( the volume of a cylinder is V=πr²h where h is height/length)

b)What is the volume of the copper into m³? Show the work

Answer 1

a) total weigh of copper = 82.3 Kg, density of coper =8.94 g/cm³ , diameter of wire = 7.25 mm(0.725 cm)

density of coper = mass of copper / volume of copper

volume of copper V = ( 82300 g / 8.94 g/cm³ ) = 9205.81 cm³ = 0.00920581 m³

volume of wire = πr²h ..........{ r = 0.3625 cm ,  π = 22/7 , h = height of wire or length }

height or length of wire = volume of wire / πr²

height or length of wire =( 9205.81 cm³ / 3.1428x 0.3625² cm² ) = 22290.984 cm = 222.90984 m

b) 9205.81 cm³ / (100)³ = 0.00920581 m³   ... ....(1m = 100cm )