Question

1) Back in the day, aluminum was a highly precious metal. It was first isolated by Hans Charistian Oersted (or possibly Friedrich Wohler, who believed Oersted to not have succeeded) in the early 1800s. Its synthesis involved the reaction of aluminum chloride with potassium:

3K + AlCl₃ → Al + KCl₃

The Baron Von Markov has decided that he wants a full aluminum place setting, and you have been put in charge of making the required aluminum. You have to produce 300 g of aluminum using the reaction shown above, which work in 67% yield. How much aluminum chloride (AlCl₃) and potassium (K) will you need to be able to produce the needed amount of aluminum?

Answer 1

Yield of aluminium = 67%

300gm of Al is produce in the reaction

production of Al = 300*67/100 =201gm

3K    +      AlCl3 -----> Al + KCl3

3 moles     1 mole     1 mole

From the balance equation

production of1 mole of Al to need 3 moles of K

production of 27gm of Al to need 3*39gm of K

production of 201 gm of Al to need 3*39*201/27 = 807gm gm of K

prodution of 27gm of Al to need 133.4gm of AlCl3

production of 201gm of Al to need = 133.4*201/27 = 993gm of AlCl3