Question

Ten
grams of plastic beads with a density of 1.2 g/cm^3 are added to
500 mL of an organic solvent with a density of 0.8 g/cm^3. What is
the concentration of the plastic beads in mg/L? (This is a curve
ball!)

Answer #1

mass of solute = 10 g = 10000 mg

volume of solute = mass / density = 10 / 1.2 = 8.33 mL = 0.00833 L

volume of solvent = 500 mL = 0.5 L

concentration = mass of solute / volume of solution

= 10000 / (0.5 + 0.00833)

**
= 19672 mg/L**

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