The henry's law constant of gaseous methyl bromide CH3Br is k=0.159 mol/L -atm at 25oC. what mass of gaseous CH3Br willl dissolve in 225 mL of water at 25oC and at a CH3Br partial pressure of 250 mm Hg? ( Molar Mass CH3Br=94.93)
A. 5.23 g
B. 3.40 g
C. 8.49 g
D. 22.1 g
E. 1.12 g
According to henry’s laW ,the amount of gas dissolved in any solvent is proportional to its partial pressure in the gaseous phase.
Where k=0.159 mol/L -atm =henry’s constant of gaseous methyl bromide
C=concentration of methyl bromide in water
P=partial pressure of methyl bromide=250 mm Hg=250mmHg/760 mmHg atm-1=0.329 atm
C=(0.159 mol/L –atm)*0.329 atm=0.0523 mol/L
The concentration of methyl bromide=0.0523 mol/L
Moles of methyl br in 225ml(0.225L)=0.0523 mol/L*0.225L=0.0118 mol
Mass=moles*molar mass=0.0118 mol*94.93 g/mol=1.120 g(option E)
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